Divide 39x^3(50x^2-98) by 26x^2(5x+7)
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Posted by Gauri Chhatwani 5 years, 8 months ago
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Sia ? 5 years, 8 months ago
39y3 (50y2 – 98) ÷ 26y2(5y + 7)
{tex} = \frac{{39{y^3}(50{y^2} - 98)}}{{26{y^2}(5y + 7)}}{/tex}
{tex} = \frac{{39{y^3} \times 2 \times (25{y^2} - 49)}}{{26{y^2}(5y + 7)}}{/tex}
{tex} = \frac{{39{y^3} \times 2 \times \{ {{(5y)}^2} - {{(7)}^2}\} }}{{26{y^2}(5y + 7)}}{/tex}
{tex} = \frac{{39{y^3} \times 2 \times (5y + 7)(5y - 7)}}{{26{y^2}(5y - 7)}}{/tex}. . . . [Using Identity III
= 3y (5y – 7)
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