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Find sum of all n odd …

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Find sum of all n odd natural number

Posted by Chethan Chethan 6 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 5 months ago

The given n odd natural numbers are,
1, 3, 5, .... n

Clearly,it is an AP with ,
First term (a) = 1
Common difference (d) = 3 - 1 = 2
Number of terms = {tex}{/tex}n
Sum of n terms {tex} = \frac{n}{2}\left[ {2a + (n - 1)d} \right]{/tex}
{tex} = \frac{n}{2}\left[ {2 \times 1 + (n - 1) \times 2} \right]{/tex}
{tex} = \frac{n}{2}\left[ {2 + 2n - 2} \right]{/tex}
{tex} = \frac{n}{2} \times 2n{/tex}
= n²

1Thank You

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Don't post personal information, mobile numbers and other details.
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Posted by Hari Anand 6 months, 1 week ago

CBSE > Class 10 > Mathematics