If one zero of the quadratic …
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Sia ? 6 years, 5 months ago
f(x) =4x2- 8kx + 8x - 9
= 4x2+ (8- 8k)x - 9
Let one zero = {tex}\alpha{/tex}
{tex}\therefore{/tex}other zero = -{tex}\alpha{/tex}[A.T.Q.]
Now Sum of zeroes ={tex}\frac { - b } { a }{/tex}
{tex}\Rightarrow \quad \alpha + ( - \alpha ) = \frac { - ( 8 - 8 k ) } { 4 }{/tex}{tex}\Rightarrow 0 = \frac { - 8 + 8 k } { 4 }{/tex}
{tex}\Rightarrow{/tex}-8 + 8k = 0 {tex}\Rightarrow{/tex}k = 1
Polynomial p(x) = kx2 + 3kx + 2
becomes p(x) ={tex}1 \times x ^ { 2 } + 3 \times x + 2{/tex} [Using k = 1]
= x2 + 3x + 2
For zeroes of p(x),x2 + 3x + 2 = 0
{tex}\Rightarrow{/tex} (x + 2)(x + 1) = 0
{tex}\Rightarrow{/tex} x = - 2,x = - 1
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