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if one zero of polynomial 2x^2-(3k-1) x-9 is the negative of the other find K and the zeros.

Posted by Lava Partap 8 years ago

CBSE > Class 10 > Mathematics

2 answers

Riya Lakra 7 years ago

Also find the zeros

1Thank You

Naveen Sharma 8 years ago

Ans. Polynomial : 2x² - (3k-1) x - 9

on comparing with ax²+ bx + c, we get, a = 2, b = -(3k-1) and c = -9

Let one zero = $\alpha$ ,

then second zero ll be = $- \alpha$

We know

Sum of zeroes = $-{b\over a}$

=> $-\alpha + \alpha = {-[{-({3k-1)}}]\over 2}$

=> $0 = {3k-1\over 2}$

=> 3k -1 = 0

=> 3k = 1

=> k = ${1\over 3}$

0Thank You

ANSWER

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