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(Cos^3theta-sin^3theta/costheta-sintheta)-(cos^3theta+sin^3theta/costheta+sintheta)=1

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(Cos^3theta-sin^3theta/costheta-sintheta)-(cos^3theta+sin^3theta/costheta+sintheta)=1

Posted by Vedant C Patel 6 years, 5 months ago

CBSE > Class 10 > Mathematics

2 answers

Vedant C Patel 6 years, 5 months ago

Not able to understand complrtely..

0Thank You

Gaurav Seth 6 years, 5 months ago

Use the identity (a^3+b^3)= (a+b)(a^2+b^2-ab)

sin^3A + cos^3A÷(sinA +cos ). + sinA.cosA
(sinA+cosA)(sin^2+cos^2 -sinA.cosA)÷ (sinA + cosA)+ sinA.cosA

or( sinA^2+cosA^2 -sinA.cosA) +sinA.cosA

1-sinA.cosA+sinA.cosA
1

1Thank You

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Posted by Kanika . 1 month ago

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Don't post personal information, mobile numbers and other details.
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Posted by Hari Anand 6 months, 1 week ago

CBSE > Class 10 > Mathematics