Represent the galvanic cell and write …
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Posted by Abhyuday Patel 6 years, 6 months ago
- 2 answers
Sia ? 6 years, 6 months ago
{tex}E_{(Cu^{2+}/Cu)}^\Theta=0.34V {/tex} and {tex}E_{(Ag^+/Ag)}^\Theta=0.80V {/tex}
Standard emf of Cu is less than Ag, therefore it is strong reducing agent and is oxidised. Therefore Cu acts as Anode and Ag acts as Cathode.
Half cell reactions are:
At Cathode (Reduction):
{tex}2Ag^+(aq)+2e^-\rightarrow2Ag(s){/tex}
At Anode (Oxidation):
{tex}Cu(s)\rightarrow Cu^{2+}(aq)+2e^- {/tex}
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Kashish Dogra 6 years, 6 months ago
0Thank You