Consider a uniform electric field is …
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Consider a uniform electric field is equals to 3 x 10 raise to the power 3 ICAP N/C a. what is the flux of this field through a square of 10 cm on a side whose plane is parallel to the y z plane? b. what is the flux through the same square if the normal to its plane makes 60 degree angle with the x-axis?
Posted by The Poetic Flow 6 years, 3 months ago
- 2 answers
Řøhăň Řąjpůť ✌️✊ 6 years, 3 months ago
First part answer is ➡️Electric field intensity, = 3 × 103 î N/C
➡️Magnitude of electric field intensity, |E |= 3 × 103N/C
➡️ Side of the square, s = 10 cm = 0.1 m
➡️Area of the square, A = s2 = 0.01 m2
θ = 0°
➡️Flux (Φ) through the plane is given by the relation,
Φ =|E |Acosθ
= 3 × 103 × 0.01 × cos0°
= 30 N m2/C
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Řøhăň Řąjpůť ✌️✊ 6 years, 3 months ago
2Thank You