if the zeroes of x2-kx+6 are …
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Payal Singh 8 years, 3 months ago
Let roots are {tex}\alpha \ and \ \beta {/tex}
{tex}{\alpha \over \beta } = {3\over 2}{/tex}
=> {tex}\alpha ={ 3\over 2}\beta{/tex}.....(1)
Then
Product of roots = {tex}c\over a{/tex}
=> {tex}\alpha \beta = 6{/tex}
=> {tex}{3\over 2}\beta \beta = 6{/tex}
=> {tex}\beta^2 = 4{/tex}
=> {tex}\beta = \pm 2{/tex}
Putting in (1) we get
{tex}\alpha = \pm 3{/tex}
Now sum of roots = {tex}-{b\over a}{/tex}
=> 3 + 2 = k or -3 + (-2) = k
=> k = 5 or k = -5
2Thank You