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Construct a triangle ABC with perimeter …

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Construct a triangle ABC with perimeter 11cm and each of its base angle is 45°

Posted by Ayush Karna 6 years, 6 months ago

CBSE > Class 09 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

Given: In triangle ABC, {tex}\angle{/tex}B = 45^o, {tex}\angle{/tex}C = 45^o and AB + BC + CA = 10 cm.
Required: To construct the triangle ABC.
Steps of construction :

Draw a line segment XY = AB + BC + CA = 10 cm.
Construct {tex}\angle{/tex}LXY = {tex}\angle{/tex}B = 45^o and {tex}\angle{/tex}MYX = ∠C = 45^o
Bisect {tex}\angle{/tex}LXY and {tex}\angle{/tex}MYX. Let these bisectors meet at a point A.
Draw the perpendicular bisectors PQ of AX and RS of AY.
Let PQ intersect XY at B and RS intersect XY at C.
Join AB and AC.

ABC is the required triangle.

1Thank You

ANSWER

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