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in the given figure De parallel to OQ and DE parallel to OR prove that EF parallel to OQ

Posted by Trishala Gaikwad 6 years, 6 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 6 months ago

In {tex}\triangle {/tex}OQP,DE || OQ
{tex}\frac{{PE}}{{EQ}} = \frac{{PD}}{{DO}}{/tex} .....(i)
In {tex}\triangle {/tex}OPR,DF {tex} \bot {/tex} OR
{tex}\frac{{PD}}{{DO}} = \frac{{PF}}{{FR}}{/tex} .....(ii)
From (i) and (ii) , we get
{tex}\frac{{PE}}{{EQ}} = \frac{{PF}}{{FR}}{/tex}
{tex}\therefore {/tex} From {tex}\triangle {/tex}PQR
EF {tex} \bot {/tex} OR

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