Why the( √2) in square under …

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Ram Kushwah 6 years, 7 months ago
{tex}\begin{array}{l}\sqrt2=2^{1/2}\\(\sqrt2)^2=(2^\frac12)^2\\=2^{\frac12\times2}\\=2^1\\=2\\Hence\;the\;root\;is\;removed\;\end{array}{/tex}
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