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An electric dipole of length 10cm …

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An electric dipole of length 10cm having charge 6*10^-3 placed at 30 degree with respect to a uniform field experience a torque of6√3 Nm. Find 1)magnitude of electric field 2)potential energy of dipole

Posted by Adithya T 6 years, 3 months ago

CBSE > Class 12 > Physics

4 answers

Řøhăň Řąjpůť ✌️✊ 6 years, 3 months ago

? ? ? kaha type ker gyi .. ? ? ?

Ďãřşháñăã Yadav ? ? ? 6 years, 3 months ago

mai ni change Kerne wali tu kerega maine phale se he ye topic choose ker Liya tha.

Řøhăň Řąjpůť ✌️✊ 6 years, 3 months ago

kya baat hai value put ker ke bta deti. lazy person ... ? ? ? vese gud one ✌️

Ďãřşháñăã Yadav ? ? ? 6 years, 3 months ago

1) |E| = τ/qdsinθ = 6 underoot 3/0.1×10^-3×0.5 solve this u will get 3.46×10⁴ N/C which will be ur answer. Now 2nd part of the question... we know that τ= PE sinθ nd potential energy U = - PEcosθ by dividing these two we get τ/u = - tanθ. put the value in it u will get ur answer.

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