5-√6÷5+√6

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Payal Singh 8 years, 6 months ago
{tex}5-\sqrt 6\over 5 + \sqrt 6{/tex}
Rationalize the denominator
= {tex}{5-\sqrt 6\over 5 + \sqrt 6}\times{ 5-\sqrt 6\over 5 -\sqrt 6}{/tex}
= {tex}25+6-10\sqrt 6\over 25-6{/tex}
= {tex}31 - 20\sqrt 6\over 19{/tex}
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