Show that the polynomial x^2-6x+12 has …

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Sia ? 6 years, 6 months ago
x2 - 6x + 12
Here, a = 1, b = -6 and c = 12
D = b2 - 4ac
D = (-6)2 - 4(1)(12)
D = 36 - 48
D = -12
Hence, D < 0
Therefore, there exists no real root of the equation.
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