A family spent Rs. 500 monthly …
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Sia ? 5 years, 5 months ago
According to the question x is extra milk and y is the expenditure for the month
If the quantity of extra milk be 'x' and expenditure be Rs. 'y' then the given condition.
y = 20x + 500 (As Rs.500 is the fixed expenditure) ...(i)
Put x = 0 in equation (i)
y = 20(0) + 500 = 0 + 500
y = Rs.500
When no extra milk is taken the expenditure remains Rs.500 same
Put y = 1000 in equation (i)
1000 = 20x + 500
1000 - 500 = 20x
500 = 20x
x = {tex}\frac{500}{20}=25 \mathrm{kg}{/tex}
When the 25 kg of milk is taken extra the expenditure increased as Rs.1000
<th scope="row">x</th> <th scope="row">y</th>Put x = 2 in equation (i)
y = 20(2) + 500
y = 40 + 500
y = Rs. 540
When the 2 kg of milk is taken extra the expenditure increased by Rs.40 i.e. Rs. 540
2Thank You