If a ball is thrown vertically …
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Sia ? 6 years, 6 months ago
Let body takes T sec to reach maximum height.
We know, v = u - gT
At the highest point, v = 0
T = {tex}\frac ug{/tex} ………… (i)
Velocity attained by Body in (T - t) s,
v = u - g(T - t)
= u - gT + gt = u - g{tex}\frac ug{/tex} + gt
or v = gt......(ii)
Now, Distance travelled in last t sec of its ascent
s = (gt)t -{tex}\frac 12{/tex}gt2 = {tex}\frac 12{/tex}gt2
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