No products in the cart.

Derivation of cyclotron

CBSE, JEE, NEET, CUET

CBSE, JEE, NEET, CUET

Question Bank, Mock Tests, Exam Papers

NCERT Solutions, Sample Papers, Notes, Videos

Derivation of cyclotron
  • 1 answers

Yogita Ingle 6 years, 3 months ago

  • Cyclotron is a device used to accelerate charged bodies to very high velocities (or high kinetic energies) using crossed (or mutually perpendicular) electric and magnetic fields
  • Cyclotron is based on the independency of frequency (of rotation of charged particle) on the energy (velocity) and radius (of revolution) of charged particle. The motion of charge , electric field, and the magnetic field are mutually perpendicular(θ= 90°), so:

fc = 1/T = qB(sinθ)/(2πm) = qB/(2πm)

  • Cyclotron is made up of 2 hollow metallic discs D1 and D2, semi-circular in shape and an oscillator.
  • The discs(D) perform mainly 2 functions: a) to block(shield) electric field inside it (known as electrostatic shielding) b) act as a capacitor outside the region between the 2 discs to provide some electric field
  • The oscillator’s job is to reverse the direction of electric field at the time interval of eachrevolution of charge, meaning frequency of oscillator fo should be same as the frequency of cyclotron fo.It is because when the charge moves from one D to another, the direction of electric field should always be such that the charge always accelerates(and never decelerates)
http://mycbseguide.com/examin8/

Related Questions

Derivation of ohm's law class 12
  • 0 answers
what us current
  • 2 answers

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Test Generator

Test Generator

Create papers online. It's FREE.

CUET Mock Tests

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Download myCBSEguide App