A wire is stretched to increase …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Umang Chauhan 6 years, 8 months ago
- 2 answers
Gurman Kaur 6 years, 8 months ago
As the wire is streched its length inc but area of cross section dec,the change in resistance due to both inc in length and dec in area
R={rho} l÷a
V=A×L A=V÷l
R=[rho] l sq.÷V
R=L sq. [For initial]
R'=l''(for final)
R'÷R= l'÷l whole sq.=0.05sq.
R'÷R =0.0025
Inc in % of resistance R'-R÷R×100
(0.0025-1)×100 = 9%inc
Test
Related Questions
Posted by Khushbu Otti 1 year, 7 months ago
- 0 answers
Posted by Anterpreet Kaur 1 year, 8 months ago
- 0 answers
Posted by Aniket Mahajan 1 year ago
- 0 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Sia ? 6 years, 8 months ago
R={tex}\rho{/tex}L/A
R={tex}\rho{/tex} 5%L/A/5%
R={tex}\rho{/tex}25%(L/A)
R=25%({tex}\rho{/tex}L/A)
R=25%R'
0Thank You