A wire is stretched to increase …
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Posted by Umang Chauhan 6 years, 3 months ago
- 2 answers
Gurman Kaur 6 years, 3 months ago
As the wire is streched its length inc but area of cross section dec,the change in resistance due to both inc in length and dec in area
R={rho} l÷a
V=A×L A=V÷l
R=[rho] l sq.÷V
R=L sq. [For initial]
R'=l''(for final)
R'÷R= l'÷l whole sq.=0.05sq.
R'÷R =0.0025
Inc in % of resistance R'-R÷R×100
(0.0025-1)×100 = 9%inc
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Sia ? 6 years, 3 months ago
R={tex}\rho{/tex}L/A
R={tex}\rho{/tex} 5%L/A/5%
R={tex}\rho{/tex}25%(L/A)
R=25%({tex}\rho{/tex}L/A)
R=25%R'
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