Represent root 3 on number line
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Sia ? 5 years, 5 months ago
Take AB= BC = 1cm
{tex}\angle B = {90^0}{/tex}
In {tex}\triangle{/tex}ABC
AC2 = AB2 + BC2
AC2 = 1 + 1
AC2 = 2
AC = {tex}\sqrt{2}{/tex}
In {tex}\triangle{/tex}OCD
{tex}\angle C = {90^0}{/tex}
OD2 = OC2 + DC2
OD2 = ({tex}\sqrt{2}{/tex})2 + 1
OD2 = 2 + 1
OD2 = 3
OD = {tex}\sqrt{3}{/tex}
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