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If -3 is one of the zeroes of the polynomial (k-1)x^2+kx+1, find the value of k .

Posted by Krishna Gupta 6 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 7 months ago

p(x) = (k-1)x²+ kx + 1
Since, -3 is a zero of the polynomial.
p(-3) = (k - 1)(-3)² + k(-3) + 1 = 0
9(k - 1) - 3k + 1 = 0
9k - 9 - 3k + 1 = 0
6k - 8 = 0
6k = 8
k = 8/6
k = 4/3

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