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what is the net charge of 1.0 gram gold piece after removal of 1.0 % of electron pls answer

Posted by Priya Dharshini ? 6 years, 3 months ago

CBSE > Class 12 > Physics

8 answers

Aman Kumar 6 years, 3 months ago

Thanks yarr?..ook see at the top ...there I am asking question

Priya Dharshini ? 6 years, 3 months ago

U can ask differentiation chapter... i am doing that chapter only now..

Priya Dharshini ? 6 years, 3 months ago

I know hindi, it was my second language from begining onwards...... i am comfortable in typing english than hindi, i can speak in hindi v.well being in north states i am used to it..

Aman Kumar 6 years, 3 months ago

I have doubt in differentiation chapter

Priya Dharshini ? 6 years, 3 months ago

Ya sure u can ask ur maths doubt. I am maths student only.... let me know which chapter u have doubt

Priya Dharshini ? 6 years, 3 months ago

Thanks a lot....i will solve it now ?☺☺

Aman Kumar 6 years, 3 months ago

Sequence dekh lena bus...?

Aman Kumar 6 years, 3 months ago

Mass of gold = 197.97 ~= 198 amu. therefore Moles of gold in 1.0 gm = 1/M No. of atoms in 1.0 gm gold = (1.0/M) × 6.022×10^23 .....Atomic no of gold = electrons in one gold atom = 79. Therefore, charge on whole 1.0 gm = (1/M).An.79 Calculate 1% of above. charge (1/M).An.79.(0.01) = 0.024 ×10^23 therefore charge carried by 1% of electrons = 0.024 × 10^23 ×(-1.6 × 10^-19 C)

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