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, the floor of a rectangular hall has a perimeter 250m if the cost of the painting the four walls rupees 10 per metre square is Rupees 1500 find the height of the hall

Posted by Keshav Deshmukh 5 years, 5 months ago

CBSE > Class 09 > Mathematics

1 answers

Sia ? 5 years, 5 months ago

Given: Perimeter of rectangular wall = {tex}2\left( l+b \right){/tex} = 250 m ……….(i)
Now Area of the four walls of the room
={tex}\frac{\text{Total cost to paint walls of the room}}{\text{Cost to paint 1 }{{\text{m}}^{2}}\text{ of the walls}}{/tex}
={tex}\frac{15000}{10} = 1500 {{m}^{2}}{/tex} ……….(ii)
{tex}\because{/tex} Area of the four walls = Lateral surface area = {tex}2\left( bh+hl \right){/tex}={tex}2h\left( b+l \right){/tex} = 1500
{tex}\Rightarrow {/tex} {tex}250\times h=1500{/tex} [using eq. (i) and (ii)
{tex}\Rightarrow {/tex} {tex}h=\frac{1500}{250}{/tex} = 6 m
Hence required height of the hall is 6 m.

1Thank You

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CBSE > Class 09 > Mathematics