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We need to find two consecutive odd integers, the sum of whose square is 202

Posted by Tanya ?? Mishra 6 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Ram Kushwah 6 years, 7 months ago

let the consecutive odd integers are x and x+2

then x²+(x+2)²=202

x²+x²+4x+4-202=0

2x²+4x-198=0

x²+2x-99=0

x²+11x-9x-99=0

x(x+11)-9(x+11)=0

(x+11)(x-9)=0

x=-11,9

So other no are -11+2 ad 9+2 or -9,11

So the numbers are
9,11 or -9,-11

1Thank You

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