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ABCD is a square of side …

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ABCD is a square of side 5m . Charges of +50 C, -50 C. And +50C are placed at A,Cand D respectively fibd the resultant electric field at B
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Electric field due to A ➡️ EA =k ×50/5 ²__________ Electric field due to B ➡️ EB =k×50/5²_____ E (net) ➡️ sqrt of EA²+EB² which give ➡️ underoot 2 ×k×50/5²______ Electric field due to charge at C.________ Ec➡️ k×50/5²____ E'(net) ➡️ sqrt of E(net) ²+Ec²= by solving this u will get ur answer 27×10^9 v/m. along AB.
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