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In the adjacent figure if x:y= 11:19 AD parallel BE FIND angle DCE

Posted by Divya Gupta 5 years ago

CBSE > Class 09 > Mathematics

1 answers

Sia ? 5 years, 10 months ago

According to question, x : y = 11 : 19
Therefore, x = 11a and y = 19 a
Now, AD is parallel to BE
So
$\angle$ BDC = $\angle$ ABD
y  = 32
19 a = 32
So   a = $\frac{32}{19}$
Thus  x = $11 \times \frac{32}{19}$
x = 18.52
Since $\angle$ DCE = $\angle$ ADC
So. $\angle$ DCE = x + 32 = 18.52 + 32 = 50.32

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