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For what values of k are the roots of the quadratic equation 3xsq +2kx+27=0 real and equal

Posted by Mahak Mittal 6 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 7 months ago

We have the following equation,
3x² - 2kx + 27 = 0
a = 3, b = -2k and c = 27
{tex}\therefore{/tex} D = b² - 4ac
= (-2k)² - 4(3)(27)
= 4k² - 324
Roots are real and equal if D = 0
{tex}\Rightarrow{/tex} 4k² - 324 = 0
k²= {tex}\frac { 324 } { 4 }{/tex} = 81
{tex}\therefore k = \pm 9{/tex}

4Thank You

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CBSE > Class 10 > Mathematics