sin11asin7a+sinasin3a/cos11asin3a+cos7asina=tan8a prove this
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Tanvi Chauhan?? 6 years, 6 months ago
- 1 answers
Test
Related Questions
Posted by Manoj Thakur 1 year, 4 months ago
- 0 answers
Posted by Sana Dharwad 1 year, 4 months ago
- 0 answers
Posted by Ashish Chaudhary 1 year, 4 months ago
- 1 answers
Posted by Ananya Sv 1 year, 5 months ago
- 1 answers
Posted by Sethpoulou Apoulou 1 year, 5 months ago
- 0 answers
Posted by Nitin Kumar 1 year, 4 months ago
- 1 answers
Posted by Sabin Sultana 1 year, 4 months ago
- 0 answers
Posted by Gurleen Kaur 1 year, 5 months ago
- 0 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Sia ? 6 years, 6 months ago
sin11asina+sin7asin3a/cos11asina+cos7asin3a
=2sin11asina+2sin7asin3a/2cos11asina+2cos7asin3a
=[{cos(11a-a)-cos(11a+a)}+{cos(7a-3a)-cos(7a+3a)}]/
[{sin(11a+a)-sin(11a-a)}+{sin(7a+3a)-sin(7a-3a)}]
=(cos10a-cos12a+cos4a-cos10a)/(sin12a-sin10a+sin10a-sin4a)
=(cos4a-cos12a)/(sin12a-sin4a)
=[2sin(4a+12a)/2sin(12a-4a)/2]/[2cos(12a+4a)/2sin(12a-4a)/2]
=sin8asin4a/cos8asin4a
=sin8a/cos8a
=tan 8a
1Thank You