How long will a passenger sitting …
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Sia ? 6 years, 6 months ago
54 {tex}\times \frac{5}{18}{/tex} = 15 m/s
36 {tex}\times \frac{5}{18}{/tex} = 10 m/s
The relative speed of two approaching bodies is the sum of the two speeds.
In this case we have :
Relative speed : 15 + 10 = 25 m/s
Relative distance is 150 m
Time = {tex}\frac{\text{Distance}}{\text{Time}}{/tex}= {tex}\frac{150}{25}{/tex}= 5
Time is therefore 5 seconds
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