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Explain why for any charge configuration …

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Explain why for any charge configuration the other equipotential surface through a point is normal to the electric field at that point
  • 1 answers

Sia ? 6 years, 4 months ago

No work is done in movmg a test charge from one point on an equipotential surface to the other.
{tex}W _ { B } - W _ { A } = 0 = - \int E \; dl \Rightarrow \vec E \cdot \vec {d l} = 0{/tex}, Say WB - WA is the work done to move a test charge from point A to point B on an equipotential surface.
Hence, {tex}\vec E \perp \vec {d l}{/tex}

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