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For what value of k will the given pair of linear equation have unique solution? x + 3y = 5 and 3x + ky - 15 = 0

Posted by Rimzim Mhaske 6 years, 7 months ago

CBSE > Class 10 > Mathematics

2 answers

Manish Kumar 6 years, 7 months ago

Value of k is 3

1Thank You

Sia ? 6 years, 7 months ago

The given pair of linear equations is
x + 3y - 5 = 0
3x + ky - 15 = 0
{tex}\Rightarrow{/tex} x + 2y - 5= 0
Here, a₁ = 1, b₁ = 3, c₁ = -5
a₂ = 3, b₂ = k, c₂ = -15

For having a unique solution, we must have
{tex}\frac { a _ { 1 } } { a _ { 2 } } \neq \frac { b _ { 1 } } { b _ { 2 } }{/tex}
{tex}\Rightarrow \quad \frac { 1 } { 3 } \neq \frac { 3 } { k } \Rightarrow k \neq 9{/tex}

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CBSE > Class 10 > Mathematics