Express 0.6+0.7bar + 0.47bar in the …
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Sia ? 6 years ago
We have 0.6=610 ...(1)
Let x=0.ˉ7=0.777... ...(2)
Subtracting (1) from (2), we get
9x = 7 ⇒x=79 or 0.ˉ7=79
Now, let y=0.4ˉ7=0.4777...
∴10y=4.ˉ7 ...(3)
And 100y=47.ˉ7 ...(4)
Subtracting (3) from (4), we get
90y = 43 ⇒y=4390
∴0.4ˉ7=4390
Now, 0.6+0.ˉ7+0.4ˉ7=610+79+4390=54+70+4390=16790
So, 16790 is of the form pq and q≠0.
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