An electrician has to repair an …

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Sia ? 6 years, 7 months ago
Let AC be the electric pole of height 4 m. Let B be a point 1.3 m below the top A of the pole AC.

Then {tex}BC=AC-AB=4-1.7=2.3 m{/tex}
Here BD is the ladder and
{tex}\angle BDC{/tex} = 60o
In {tex}\triangle{/tex}BCD, we have
{tex}\frac{BD}{BC} =cosec60=\frac{2}{√3}{/tex}
BD = BC {tex}\times{/tex} {tex}2\over √3{/tex}
= 2.7 {tex}\times{/tex} {tex}\frac{2}{1.73} = 3.12 m{/tex}
Hence length of ladder = 3.12 meter
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