Aditya has built a cubical water …
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Aditya has built a cubical water tank with lid, for his house, with each outer edge 1.5m long. He gets the outer surface of tank excluuding the base, covered with square tiles of 25 cm. Find how much he would spend for tiles, if the cost of tiles is Rs480 per dozen.
Posted by Rajbeer Kaur 5 years, 5 months ago
- 1 answers
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Sia ? 5 years, 5 months ago
Each edge of tank = 1.5 m = 1.5{tex}\times{/tex} 100 cm = 150 cm
Area of five faces of the tank = 5 (side)2 = 5a2 = 5 (150 cm)2 = 5 (22500) = 1,12,500 cm2
Area of a square tile = 25 cm {tex}\times{/tex} 25 cm = 625 cm2
Number of tiles required = {tex}\frac{Area \ of \ five \ walls}{Area \ of \ a \ tile}{/tex} = {tex}\frac{1,12,500 }{625}{/tex} = 180 tiles ={tex}\frac{180}{12}{/tex}dozen
Cost of one dozen of tiles = ₹ 480
{tex}\Rightarrow{/tex}Cost of {tex}\frac{180}{12}{/tex}dozen tiles = ₹480{tex}\times{/tex}{tex}\frac{180}{12}{/tex}= ₹ 7,200
Hence the cost of total tiles required for tank is ₹ 7,200
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