Calculate the weight of water in …
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Sia ? 6 years, 7 months ago
Given, Molarity of solution, M = 2 mol L-1
Mass of NaCl in 1 L solution = 2 {tex}\times{/tex} 58.5 = 119.0 g
Mass of 1 L solution = Volume x density of solution = 1000 mL {tex}\times{/tex} 1.2 g/mL = 1200 g (since density = 1.2 g mL-1 )
Mass of water solution = 1200 -119.0 = 1081 g = 1.081 kg.
Now, Molality of solution = {tex}\frac { \text { number of moles of solute } } { \text { mass of solvent in } \mathrm { kg } }{/tex} = {tex}\frac { 2 \mathrm { mol } } { 1.081\mathrm { kg } } = 1.85\mathrm { m }{/tex}.
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