Explain [Co(NH3)6]+3 is an inner orbital …
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Sia ? 6 years, 7 months ago
In [CO(NH3)6]3+ oxidation state of CO = +3
Configuration = 3d6
In presence of NH3, 3d electrons pair up leaving two d-orbitals empty. Hence, the hybridization is d2sp3 forming an inner orbital complex.
In [Ni(NH3)6]2+
Oxidation state = +2. Electronic configuration = 3d8. In presence of NH3, 3d electrons do not pair up. The hybridization involved is sp3d2and forming an outer orbital complex.
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