If 5+2√3÷7+4√3=k-6√3 find the value of …

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Yogita Ingle 6 years, 6 months ago
LHS = (5+2√3)/(7+4√3)
= [(5+2√3)(7-4√3)]/[(7-4√3)(7+4√3)]
=[35-20√3+14√3-24]/[7²-(4√3)²]
=[11-6√3]/[49-48]
=11-6√3
therefore
11 - 6√3 = a + b√3
Compare both sides
a= 11, b= -6
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