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Kx+y=ksquare and x+ky=1 have infinitely many …

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Kx+y=ksquare and x+ky=1 have infinitely many solutions
  • 1 answers

Sia ? 6 years, 7 months ago

{tex}k x + y = k ^ { 2 } \text { and } x + k y = 1{/tex}
{tex}a_1 = k , b_1 = 1, c_1= k^2{/tex}
and {tex}a_2 = 1, b_2 = k , c_2 = 1{/tex}

{tex}\frac { a _ { 1 } } { a _ { 2 } } = \frac { k } { 1 } , \frac { b _ { 1 } } { b _ { 2 } } = \frac { 1 } { k } , \frac { c _ { 1 } } { c _ { 2 } } = \frac { k ^ { 2 } } { 1 }{/tex}

For infinitely many solution

{tex}\frac { a _ { 1 } } { a _ { 2 } } = \frac { b _ { 1 } } { b _ { 2 } } = \frac { c _ { 1 } } { c _ { 2 } }{/tex}

{tex}\frac { k } { 1 } = \frac { 1 } { k } = \frac { k ^ { 2 } } { 1 } {/tex}
{tex}\frac { k } { 1 } = \frac { 1 } { k }{/tex}
{tex} k ^ { 2 } = 1{/tex}

{tex}k = \pm 1{/tex}

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