Express the 0.12 and bar on …
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Sia ? 5 years, 11 months ago
Let we have ,
x=0.1¯2, then
x = 0.12222....
⟹10x = 1.2222.... ...(i)
⟹100x= 12.2222... ...(ii)
Subtracting (i) from (ii), we get
⟹100x-10x=11
⟹90x=11∴x=1190
Thus the value of x =0.1¯2 is equal to 1190
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