IF A(5,2) B(2,-2) and C(-2,t) are …

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Sia ? 6 years, 6 months ago
we are given that A (5, 2), B (2, - 2) and C (-2, t) are the vertices of a right-angled triangle with {tex}\angle B{/tex} = 90°.
AB2 = ( 2 - 5)2 + ( - 2 - 2)2 =9 + 16 = 25
BC2 = (- 2 - 2)2 + (t + 2)2 = 16 + (t + 2)2
AC2 = (5 + 2)2 + (2 - t)2 = 49 + (2 - t)2
Since {tex}\triangle{/tex}ABC is a right angled triangle
{tex}\therefore{/tex} AC2 = AB2 + BC2
or, 49 + (2 - t)2 = 25 + 16 + (t + 2)2
or, 49 + 4 - 4t + t2 = 41 + t2 + 4t + 4
or, 53 - 4t = 45 + 4t
or, 8t = 8
{tex}\therefore{/tex} t =1
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