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IF the point A(0,2) IS EQUIDISTANCE …

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IF the point A(0,2) IS EQUIDISTANCE from the point B(3,p) and c(p,5) find p alwo find the length of ab

    • Posted by Gopinath Messi 6 years, 4 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Sia ? 6 years, 4 months ago

    A(0, 2) is equidistant from B(3, p) and C(p, 5). Therefore,
    AB = AC
    AB2 = AC2
    (3 - 0)2 + (p - 2)2 = (p - 0)2 + (5 - 2)2
    32 + p2 + 4 - 4p = p2 + 9
    9 + 4 - 4p = 9
    4 - 4p = 0
    4 = 4p
    p = 1
    AB = {tex}\sqrt{(3-0)^2+(p-2)^2}=\sqrt{9+(1-2)^2}{/tex}{tex}=\sqrt{10}{/tex}

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