∆ABC~∆DEF, If DE = 2AB and …

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Sia ? 6 years, 7 months ago
Given that {tex}\triangle{/tex}ABC ~ {tex}\triangle{/tex}DEF
We know that when two triangles are similar, then the ratios of the lengths of their corresponding sides are equal.
{tex}\Rightarrow \frac { A B } { D E } = \frac { B C } { E F }{/tex}
{tex}\Rightarrow \frac { 1 } { 2 } = \frac { 3 } { E F }{/tex}
{tex}\Rightarrow{/tex} EF = {tex}\frac 32{/tex} cm
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