Well with 10 metre inside diameter …
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Sia ? 5 years, 5 months ago
Given the diameter = 10 m
So, the radius of the well = 5 m
Height of the well = 14 m
Width of the embankment = 5m
Therefore, radius of the embankment = 5 + 5 =10 m
Let h' be the height of the embankment,
Hence, the volume of the embankment = Volume of the well
That is, {tex}\pi{/tex}(R - r)2h' = {tex}\pi r ^ { 2 } h{/tex}
{tex}\Rightarrow{/tex} (102 - 52) {tex}\times{/tex} h' = 52 {tex}\times{/tex} 14
{tex}\Rightarrow{/tex} (100 - 25) {tex}\times{/tex} h' = 25 {tex}\times{/tex} 14
{tex}\Rightarrow h' = \frac { 25 \times 14 } { 75 } = \frac { 14 } { 3 }{/tex}
Therefore, h' = 4.67 cm approximately.
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