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Find the value of k so that the pair of linear equations x+2y =5 and 3x+ky+5=0 have unique solution

Posted by Movie Hub 6 years, 7 months ago

CBSE > Class 10 > Mathematics

2 answers

Sia ? 6 years, 7 months ago

The given pair of linear equations is
x + 2y - 5= 0 and 3x + ky + 5 = 0
Here, a₁ = 1, b₁ = 2,
a₂ = 3, b₂ = k
For having a unique solution, we must have
{tex}\frac { a _ { 1 } } { a _ { 2 } } \neq \frac { b _ { 1 } } { b _ { 2 } }{/tex}
{tex}\Rightarrow \quad \frac { 1 } { 3 } \neq \frac { 2 } { k } \Rightarrow k \neq 6{/tex}

0Thank You

Akshya V 6 years, 7 months ago

Unique solution=a1/a2 not equal to b1/b2 here, a1=1; a2=3; b1=2; b2=k then, 1/3=1/k cross multiply thn k =3

0Thank You

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CBSE > Class 10 > Mathematics