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x+a X + a is a …

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x+a X + a is a factor of two polynomial X square + PX + q and X square + M X + n prove that a a is equal to n minus Q by a minus b
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Sia ? 6 years, 7 months ago

If  (x+a)is a factor of {tex}{x^2} + px + q{/tex}  and {tex}{x^2} + mx + n{/tex}

then {tex}{( - a)^2} + p( - a) + q = {( - a)^2} + m( - a) + n{/tex}{tex}[\because x = - a]{/tex}

{tex} \Rightarrow - pa + q = - am + n{/tex}

{tex}\Rightarrow n - q = a(m - p){/tex}

{tex} \Rightarrow a = \frac{{m - p}}{{n - q}}{/tex}

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