Compute the median for each of …

CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Related Questions
Posted by Kanika . 2 months ago
- 1 answers
Posted by Parinith Gowda Ms 4 months, 2 weeks ago
- 1 answers
Posted by Hari Anand 7 months ago
- 0 answers
Posted by Lakshay Kumar 1 year, 1 month ago
- 0 answers
Posted by Sahil Sahil 1 year, 5 months ago
- 2 answers
Posted by Parinith Gowda Ms 4 months, 2 weeks ago
- 0 answers
Posted by Vanshika Bhatnagar 1 year, 5 months ago
- 2 answers

myCBSEguide
Trusted by 1 Crore+ Students

Test Generator
Create papers online. It's FREE.

CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
myCBSEguide
Sia ? 6 years, 7 months ago
We have
N=100
{tex}\therefore \quad \frac { N } { 2 } = \frac { 100 } { 2 } = 50{/tex}
The cumulative frequency just greater than {tex}\frac { N } { 2 }{/tex} is 65 then median class is 70 - 90 such that
l = 70, f = 22, F = 43, h = 90 - 70 =20
{tex}\therefore \quad \text { Median } = l + \frac { \frac { N } { 2 } - F } { f } \times h{/tex}
{tex}= 70 + \frac { 50 - 43 } { 22 } \times 20{/tex}
{tex}= 70 + \frac { 7 \times 20 } { 22 }{/tex}
=70 + 6.36
=76.36
0Thank You