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Compute the median for each of …

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Compute the median for each of the following data MARKS. NO. OF STUDENTS Less than 10 0 Less than 30 10 Less than 50 25 Less than 70 43 Less than 90 65 Less than 110 87 Less than 130 96 Less than 150 100
  • 1 answers

Sia ? 6 years, 7 months ago

<th scope="col">
less than 10 0 0-10 0 0
less than 30 10 10-30 10 10
less than 50 25 30-50 15 25
less than 70 43 50-70 18 43(F)
less than 90 65 70-90 22(f) 65
less than 110 87 90-110 22 87
less than 130 96 110-130 9 96
less than 150 100 130-150 4 100
      N=100  

We have
N=100
{tex}\therefore \quad \frac { N } { 2 } = \frac { 100 } { 2 } = 50{/tex}
The cumulative frequency just greater than {tex}\frac { N } { 2 }{/tex} is 65 then median class is 70 - 90 such that
l = 70, f = 22, F = 43, h = 90 - 70 =20
{tex}\therefore \quad \text { Median } = l + \frac { \frac { N } { 2 } - F } { f } \times h{/tex}
{tex}= 70 + \frac { 50 - 43 } { 22 } \times 20{/tex}
{tex}= 70 + \frac { 7 \times 20 } { 22 }{/tex}
=70 + 6.36
=76.36

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