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A man starts his job with …

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A man starts his job with a certain monthly salary and earns a fixed increment every year . If his salary was 1500 after 4 years of service and 1800 after 10 years of service what was his starting salary and what is his annual increment

    • Posted by Rohit Arya 6 years, 6 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Sia ? 6 years, 6 months ago

    Let the starting salary of the man be Rs. x and the fixed annual increment be Rs.y.
    Then,
    Salary after 4 years of service = Rs. (x + 4y)
    Salary after 10 years of service = Rs. (x + 10y)
    As per given condition
    After four years salary was Rs.1500
      x + 4y =1500 .............. (i)
    And Rs.1800 after 10 years of service.
    So, x + 10y = 1800 .............. (ii)
    Subtracting equation (i) from equation (ii), we get
    (x + 10y) -  (x + 4y) = 1800 - 1500
    {tex}\Rightarrow{/tex} x + 10y - x - 4y = 300
    {tex}\Rightarrow{/tex} 6y = 300
     {tex}\Rightarrow{/tex} y =50
    Putting y = 50 in equation (i), we get
    x + 4(50) = 1500
    x = 1300.
    Hence the starting salary was Rs. 1300 and annual increment is Rs.50.

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