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Cosec^3 30× cos60×tan^45×sin^90×sec^40×cot30

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Cosec^3 30× cos60×tan^45×sin^90×sec^40×cot30

Posted by Deepika Nammi 6 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 7 months ago

We know that, cosec30°=2, cos60°=(1/2), tan45°=1=sin90°, sec45°=√2 & cot30°=√3,
putting these values in the given expression, we get:-
{tex}\cos e{c^3}30^\circ \cos 60^\circ {\tan ^3}45^\circ {\sin ^2}90^\circ {\sec ^2}45^\circ \cot 30^\circ {/tex}
{tex} = {(2)^3} \times {\left( {\frac{1}{2}} \right)} \times {(1)^3} \times {(1)^2} \times {\left( {\sqrt 2 } \right)^2} \times \sqrt 3 {/tex}
{tex} = 8 \times \frac{1}{2} \times 1 \times 1 \times 2 \times \sqrt 3 {/tex}
{tex} = 8\sqrt 3 {/tex}

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