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STATE WHICH OF THE TWO TRIANGLE GIVEN IN THE FIGURE ARE SIMILAR. ALSO ,STATE THE SIMILARITY CRITERION USED.

Posted by Vishal Kumar 6 years, 7 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 7 months ago

Here, {tex}\frac{AB}{DF}=\frac{4}{6}=\frac{2}{3}{/tex} , {tex}\frac{BC}{EF}=\frac{5}{7.5}=\frac{2}{3}{/tex} , {tex}\frac{AC}{DE}=\frac{3}{4.5}=\frac{2}{3}{/tex}

As, {tex}\frac{AB}{DF}=\frac{BC}{EF}=\frac{AC}{DE}{/tex}

So, {tex}\Delta ABC \sim \Delta DFE{/tex} [by SSS similarity criterion]

Hence ABC and DFE are similar triangles, but no other pairs of triangles in the given figure are similar.

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