No products in the cart.

the vapour pressure of water at …

CBSE, JEE, NEET, CUET

CBSE, JEE, NEET, CUET

Question Bank, Mock Tests, Exam Papers

NCERT Solutions, Sample Papers, Notes, Videos

the vapour pressure of water at 25°c is 25.755 term and the vapour pressure of solution containing 5gram, of, solute x, in, 100 gram of water is 23.432 .calculate molar mass of x
  • 3 answers

Sinchana Malagond 6 years, 7 months ago

Use RLVP, P°-Ps÷P°= w2×M1÷M2×w1 25.755-23.432÷25.755 = 5×18÷x×100 0.09= 9÷10x X= 10g. The molar mass of x is 10g.

Achou Leimapok 6 years, 7 months ago

Pls solve

Ujjawal Yadav 6 years, 7 months ago

Simple Use Water Boiling point 100• And RAULTS law For Non volatile substance
https://examin8.com Test

Related Questions

Can we keep caso4 using vessel justify your answer
  • 1 answers
Arrhenius concept
  • 0 answers

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Test Generator

Test Generator

Create papers online. It's FREE.

CUET Mock Tests

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Download myCBSEguide App