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√5+√3 upon √80+√48−√45−√27... Simplify

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√5+√3 upon √80+√48−√45−√27... Simplify

Posted by Arjit Agrawal 6 years, 7 months ago

CBSE > Class 09 > Mathematics

1 answers

Gaurav Seth 6 years, 7 months ago

(√5+√3)/(√80+√48-√45-√27)
=> (√5+√3)/(4√5 + 4√3 - 3√5 - 3√3)
=> (√5+√3)/[4(√5+√3) - 3(√5+√3)]
=> (√5+√3)/[(4-3)*(√5+√3)]
=> 1/(4-3)
=> 1/1
=> 1

1Thank You

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